Optimal. Leaf size=247 \[ \frac {d^2 i^2 (a+b x) \left (B \log \left (\frac {e (a+b x)}{c+d x}\right )+A\right )}{b^3 g^2}-\frac {2 d i^2 (b c-a d) \log \left (1-\frac {b (c+d x)}{d (a+b x)}\right ) \left (B \log \left (\frac {e (a+b x)}{c+d x}\right )+A\right )}{b^3 g^2}-\frac {i^2 (c+d x) (b c-a d) \left (B \log \left (\frac {e (a+b x)}{c+d x}\right )+A\right )}{b^2 g^2 (a+b x)}+\frac {2 B d i^2 (b c-a d) \text {Li}_2\left (\frac {b (c+d x)}{d (a+b x)}\right )}{b^3 g^2}-\frac {B d i^2 (b c-a d) \log (c+d x)}{b^3 g^2}-\frac {B i^2 (c+d x) (b c-a d)}{b^2 g^2 (a+b x)} \]
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Rubi [A] time = 0.52, antiderivative size = 313, normalized size of antiderivative = 1.27, number of steps used = 18, number of rules used = 13, integrand size = 40, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.325, Rules used = {2528, 2486, 31, 2525, 12, 44, 2524, 2418, 2390, 2301, 2394, 2393, 2391} \[ \frac {2 B d i^2 (b c-a d) \text {PolyLog}\left (2,-\frac {d (a+b x)}{b c-a d}\right )}{b^3 g^2}+\frac {2 d i^2 (b c-a d) \log (a+b x) \left (B \log \left (\frac {e (a+b x)}{c+d x}\right )+A\right )}{b^3 g^2}-\frac {i^2 (b c-a d)^2 \left (B \log \left (\frac {e (a+b x)}{c+d x}\right )+A\right )}{b^3 g^2 (a+b x)}+\frac {B d^2 i^2 (a+b x) \log \left (\frac {e (a+b x)}{c+d x}\right )}{b^3 g^2}-\frac {B i^2 (b c-a d)^2}{b^3 g^2 (a+b x)}-\frac {B d i^2 (b c-a d) \log ^2(a+b x)}{b^3 g^2}-\frac {B d i^2 (b c-a d) \log (a+b x)}{b^3 g^2}+\frac {2 B d i^2 (b c-a d) \log (a+b x) \log \left (\frac {b (c+d x)}{b c-a d}\right )}{b^3 g^2}+\frac {A d^2 i^2 x}{b^2 g^2} \]
Antiderivative was successfully verified.
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Rule 12
Rule 31
Rule 44
Rule 2301
Rule 2390
Rule 2391
Rule 2393
Rule 2394
Rule 2418
Rule 2486
Rule 2524
Rule 2525
Rule 2528
Rubi steps
\begin {align*} \int \frac {(15 c+15 d x)^2 \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{(a g+b g x)^2} \, dx &=\int \left (\frac {225 d^2 \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^2 g^2}+\frac {225 (b c-a d)^2 \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^2 g^2 (a+b x)^2}+\frac {450 d (b c-a d) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^2 g^2 (a+b x)}\right ) \, dx\\ &=\frac {\left (225 d^2\right ) \int \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right ) \, dx}{b^2 g^2}+\frac {(450 d (b c-a d)) \int \frac {A+B \log \left (\frac {e (a+b x)}{c+d x}\right )}{a+b x} \, dx}{b^2 g^2}+\frac {\left (225 (b c-a d)^2\right ) \int \frac {A+B \log \left (\frac {e (a+b x)}{c+d x}\right )}{(a+b x)^2} \, dx}{b^2 g^2}\\ &=\frac {225 A d^2 x}{b^2 g^2}-\frac {225 (b c-a d)^2 \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2 (a+b x)}+\frac {450 d (b c-a d) \log (a+b x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2}+\frac {\left (225 B d^2\right ) \int \log \left (\frac {e (a+b x)}{c+d x}\right ) \, dx}{b^2 g^2}-\frac {(450 B d (b c-a d)) \int \frac {(c+d x) \left (-\frac {d e (a+b x)}{(c+d x)^2}+\frac {b e}{c+d x}\right ) \log (a+b x)}{e (a+b x)} \, dx}{b^3 g^2}+\frac {\left (225 B (b c-a d)^2\right ) \int \frac {b c-a d}{(a+b x)^2 (c+d x)} \, dx}{b^3 g^2}\\ &=\frac {225 A d^2 x}{b^2 g^2}+\frac {225 B d^2 (a+b x) \log \left (\frac {e (a+b x)}{c+d x}\right )}{b^3 g^2}-\frac {225 (b c-a d)^2 \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2 (a+b x)}+\frac {450 d (b c-a d) \log (a+b x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2}-\frac {\left (225 B d^2 (b c-a d)\right ) \int \frac {1}{c+d x} \, dx}{b^3 g^2}+\frac {\left (225 B (b c-a d)^3\right ) \int \frac {1}{(a+b x)^2 (c+d x)} \, dx}{b^3 g^2}-\frac {(450 B d (b c-a d)) \int \frac {(c+d x) \left (-\frac {d e (a+b x)}{(c+d x)^2}+\frac {b e}{c+d x}\right ) \log (a+b x)}{a+b x} \, dx}{b^3 e g^2}\\ &=\frac {225 A d^2 x}{b^2 g^2}+\frac {225 B d^2 (a+b x) \log \left (\frac {e (a+b x)}{c+d x}\right )}{b^3 g^2}-\frac {225 (b c-a d)^2 \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2 (a+b x)}+\frac {450 d (b c-a d) \log (a+b x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2}-\frac {225 B d (b c-a d) \log (c+d x)}{b^3 g^2}+\frac {\left (225 B (b c-a d)^3\right ) \int \left (\frac {b}{(b c-a d) (a+b x)^2}-\frac {b d}{(b c-a d)^2 (a+b x)}+\frac {d^2}{(b c-a d)^2 (c+d x)}\right ) \, dx}{b^3 g^2}-\frac {(450 B d (b c-a d)) \int \left (\frac {b e \log (a+b x)}{a+b x}-\frac {d e \log (a+b x)}{c+d x}\right ) \, dx}{b^3 e g^2}\\ &=\frac {225 A d^2 x}{b^2 g^2}-\frac {225 B (b c-a d)^2}{b^3 g^2 (a+b x)}-\frac {225 B d (b c-a d) \log (a+b x)}{b^3 g^2}+\frac {225 B d^2 (a+b x) \log \left (\frac {e (a+b x)}{c+d x}\right )}{b^3 g^2}-\frac {225 (b c-a d)^2 \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2 (a+b x)}+\frac {450 d (b c-a d) \log (a+b x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2}-\frac {(450 B d (b c-a d)) \int \frac {\log (a+b x)}{a+b x} \, dx}{b^2 g^2}+\frac {\left (450 B d^2 (b c-a d)\right ) \int \frac {\log (a+b x)}{c+d x} \, dx}{b^3 g^2}\\ &=\frac {225 A d^2 x}{b^2 g^2}-\frac {225 B (b c-a d)^2}{b^3 g^2 (a+b x)}-\frac {225 B d (b c-a d) \log (a+b x)}{b^3 g^2}+\frac {225 B d^2 (a+b x) \log \left (\frac {e (a+b x)}{c+d x}\right )}{b^3 g^2}-\frac {225 (b c-a d)^2 \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2 (a+b x)}+\frac {450 d (b c-a d) \log (a+b x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2}+\frac {450 B d (b c-a d) \log (a+b x) \log \left (\frac {b (c+d x)}{b c-a d}\right )}{b^3 g^2}-\frac {(450 B d (b c-a d)) \operatorname {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,a+b x\right )}{b^3 g^2}-\frac {(450 B d (b c-a d)) \int \frac {\log \left (\frac {b (c+d x)}{b c-a d}\right )}{a+b x} \, dx}{b^2 g^2}\\ &=\frac {225 A d^2 x}{b^2 g^2}-\frac {225 B (b c-a d)^2}{b^3 g^2 (a+b x)}-\frac {225 B d (b c-a d) \log (a+b x)}{b^3 g^2}-\frac {225 B d (b c-a d) \log ^2(a+b x)}{b^3 g^2}+\frac {225 B d^2 (a+b x) \log \left (\frac {e (a+b x)}{c+d x}\right )}{b^3 g^2}-\frac {225 (b c-a d)^2 \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2 (a+b x)}+\frac {450 d (b c-a d) \log (a+b x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2}+\frac {450 B d (b c-a d) \log (a+b x) \log \left (\frac {b (c+d x)}{b c-a d}\right )}{b^3 g^2}-\frac {(450 B d (b c-a d)) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {d x}{b c-a d}\right )}{x} \, dx,x,a+b x\right )}{b^3 g^2}\\ &=\frac {225 A d^2 x}{b^2 g^2}-\frac {225 B (b c-a d)^2}{b^3 g^2 (a+b x)}-\frac {225 B d (b c-a d) \log (a+b x)}{b^3 g^2}-\frac {225 B d (b c-a d) \log ^2(a+b x)}{b^3 g^2}+\frac {225 B d^2 (a+b x) \log \left (\frac {e (a+b x)}{c+d x}\right )}{b^3 g^2}-\frac {225 (b c-a d)^2 \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2 (a+b x)}+\frac {450 d (b c-a d) \log (a+b x) \left (A+B \log \left (\frac {e (a+b x)}{c+d x}\right )\right )}{b^3 g^2}+\frac {450 B d (b c-a d) \log (a+b x) \log \left (\frac {b (c+d x)}{b c-a d}\right )}{b^3 g^2}+\frac {450 B d (b c-a d) \text {Li}_2\left (-\frac {d (a+b x)}{b c-a d}\right )}{b^3 g^2}\\ \end {align*}
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Mathematica [A] time = 0.23, size = 221, normalized size = 0.89 \[ \frac {i^2 \left (2 d (b c-a d) \log (a+b x) \left (B \log \left (\frac {e (a+b x)}{c+d x}\right )+A\right )-\frac {(b c-a d)^2 \left (B \log \left (\frac {e (a+b x)}{c+d x}\right )+A\right )}{a+b x}+B d^2 (a+b x) \log \left (\frac {e (a+b x)}{c+d x}\right )+B d (a d-b c) \left (\log (a+b x) \left (\log (a+b x)-2 \log \left (\frac {b (c+d x)}{b c-a d}\right )\right )-2 \text {Li}_2\left (\frac {d (a+b x)}{a d-b c}\right )\right )-\frac {B (b c-a d)^2}{a+b x}+B d (a d-b c) \log (a+b x)+A b d^2 x\right )}{b^3 g^2} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.72, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {A d^{2} i^{2} x^{2} + 2 \, A c d i^{2} x + A c^{2} i^{2} + {\left (B d^{2} i^{2} x^{2} + 2 \, B c d i^{2} x + B c^{2} i^{2}\right )} \log \left (\frac {b e x + a e}{d x + c}\right )}{b^{2} g^{2} x^{2} + 2 \, a b g^{2} x + a^{2} g^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.14, size = 1465, normalized size = 5.93 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 1.91, size = 992, normalized size = 4.02 \[ -A {\left (\frac {a^{2}}{b^{4} g^{2} x + a b^{3} g^{2}} - \frac {x}{b^{2} g^{2}} + \frac {2 \, a \log \left (b x + a\right )}{b^{3} g^{2}}\right )} d^{2} i^{2} + 2 \, A c d i^{2} {\left (\frac {a}{b^{3} g^{2} x + a b^{2} g^{2}} + \frac {\log \left (b x + a\right )}{b^{2} g^{2}}\right )} - B c^{2} i^{2} {\left (\frac {\log \left (\frac {b e x}{d x + c} + \frac {a e}{d x + c}\right )}{b^{2} g^{2} x + a b g^{2}} + \frac {1}{b^{2} g^{2} x + a b g^{2}} + \frac {d \log \left (b x + a\right )}{{\left (b^{2} c - a b d\right )} g^{2}} - \frac {d \log \left (d x + c\right )}{{\left (b^{2} c - a b d\right )} g^{2}}\right )} - \frac {A c^{2} i^{2}}{b^{2} g^{2} x + a b g^{2}} - \frac {{\left (b^{2} c^{2} d i^{2} + a b c d^{2} i^{2} - a^{2} d^{3} i^{2}\right )} B \log \left (d x + c\right )}{b^{4} c g^{2} - a b^{3} d g^{2}} + \frac {{\left (b^{3} c d^{2} i^{2} \log \relax (e) - a b^{2} d^{3} i^{2} \log \relax (e)\right )} B x^{2} + {\left (a b^{2} c d^{2} i^{2} \log \relax (e) - a^{2} b d^{3} i^{2} \log \relax (e)\right )} B x + {\left ({\left (b^{3} c^{2} d i^{2} - 2 \, a b^{2} c d^{2} i^{2} + a^{2} b d^{3} i^{2}\right )} B x + {\left (a b^{2} c^{2} d i^{2} - 2 \, a^{2} b c d^{2} i^{2} + a^{3} d^{3} i^{2}\right )} B\right )} \log \left (b x + a\right )^{2} + {\left (2 \, {\left (i^{2} \log \relax (e) + i^{2}\right )} a b^{2} c^{2} d - 3 \, {\left (i^{2} \log \relax (e) + i^{2}\right )} a^{2} b c d^{2} + {\left (i^{2} \log \relax (e) + i^{2}\right )} a^{3} d^{3}\right )} B + {\left ({\left (b^{3} c d^{2} i^{2} - a b^{2} d^{3} i^{2}\right )} B x^{2} + {\left (2 \, b^{3} c^{2} d i^{2} \log \relax (e) - 4 \, {\left (i^{2} \log \relax (e) - i^{2}\right )} a b^{2} c d^{2} + {\left (2 \, i^{2} \log \relax (e) - 3 \, i^{2}\right )} a^{2} b d^{3}\right )} B x - {\left (4 \, a^{2} b c d^{2} i^{2} \log \relax (e) - 2 \, {\left (i^{2} \log \relax (e) + i^{2}\right )} a b^{2} c^{2} d - {\left (2 \, i^{2} \log \relax (e) - i^{2}\right )} a^{3} d^{3}\right )} B\right )} \log \left (b x + a\right ) - {\left ({\left (b^{3} c d^{2} i^{2} - a b^{2} d^{3} i^{2}\right )} B x^{2} + {\left (a b^{2} c d^{2} i^{2} - a^{2} b d^{3} i^{2}\right )} B x + {\left (2 \, a b^{2} c^{2} d i^{2} - 3 \, a^{2} b c d^{2} i^{2} + a^{3} d^{3} i^{2}\right )} B + 2 \, {\left ({\left (b^{3} c^{2} d i^{2} - 2 \, a b^{2} c d^{2} i^{2} + a^{2} b d^{3} i^{2}\right )} B x + {\left (a b^{2} c^{2} d i^{2} - 2 \, a^{2} b c d^{2} i^{2} + a^{3} d^{3} i^{2}\right )} B\right )} \log \left (b x + a\right )\right )} \log \left (d x + c\right )}{a b^{4} c g^{2} - a^{2} b^{3} d g^{2} + {\left (b^{5} c g^{2} - a b^{4} d g^{2}\right )} x} + \frac {2 \, {\left (b c d i^{2} - a d^{2} i^{2}\right )} {\left (\log \left (b x + a\right ) \log \left (\frac {b d x + a d}{b c - a d} + 1\right ) + {\rm Li}_2\left (-\frac {b d x + a d}{b c - a d}\right )\right )} B}{b^{3} g^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (c\,i+d\,i\,x\right )}^2\,\left (A+B\,\ln \left (\frac {e\,\left (a+b\,x\right )}{c+d\,x}\right )\right )}{{\left (a\,g+b\,g\,x\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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